Is there any reason to do anything more complicated than one of these two lines when you want to clear a list in Python:
old_list =  old_list = list()
The reason I ask is that I just saw this in some running code:
del old_list[ 0:len(old_list) ]
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Clearing a list in place will affect all other references of the same list.
For example, this method doesn’t affect other references:
>>> a = [1, 2, 3] >>> b = a >>> a =  >>> print(a)  >>> print(b) [1, 2, 3]
But this one does:
>>> a = [1, 2, 3] >>> b = a >>> del a[:] # equivalent to del a[0:len(a)] >>> print(a)  >>> print(b)  >>> a is b True
You could also do:
>>> a[:] = 
It appears to me that del will give you the memory back, while assigning a new list will make the old one be deleted only when the gc runs.matter.
This may be useful for large lists, but for small list it should be negligible.
Edit: As Algorias, it doesn’t matter.
del old_list[ 0:len(old_list) ]
is equivalent to
There are two cases in which you might want to clear a list:
- You want to use the name old_list further in your code;
- You want the old list to be garbage collected as soon as possible to free some memory;
In case 1 you just go on with the assigment:
old_list =  # or whatever you want it to be equal to
In case 2 the del statement would reduce the reference count to the list object the name old list points at. If the list object is only pointed by the name old_list at, the reference count would be 0, and the object would be freed for garbage collection.
There is a very simple way to delete a python list. Use del list_name[:].
a = [1, 2, 3] b = a del a[:] print b
Will delete the values of that list variable
Will delete the variable itself from memory
If you’re clearing the list, you, obviously, don’t need the list anymore. If so, you can just delete the entire list by simple del method.
a = [1, 3, 5, 6] del a # This will entirely delete a(the list).
But in case, you need it again, you can reinitialize it. Or just simply clear its elements by
another solution that works fine is to create empty list as a reference empty list.
empt_list = 
for example you have a list as a_list = [1,2,3]. To clear it just make the following:
a_list = list(empt_list)
this will make a_list an empty list just like the empt_list.
To clear a list in-place in Python 3.3+ you can also use list.clear(), which is consistent with the interfaces of other mutable containers (such as dict, set or deque).
old_list.clear() # removes all items from old_list (same as del old_list[:])